min

Returns minimum element in a sequence. More...

Functions
template<typename = void>
auto	coveo::linq::min () -> detail::min_impl_0<>
	Returns minimum element in sequence. More...
template<typename Selector >
auto	coveo::linq::min (const Selector &sel) -> detail::min_impl_1< Selector >
	Returns minimum projected value in sequence. More...

Detailed Description

The min operator returns the minimum element in a sequence. If the sequence does not have elements, an exception is thrown.

This is a terminal operator.

.NET equivalent: Min

Function Documentation

min() [1/2]

template<typename = void>

auto coveo::linq::min

(

)

-> detail::min_impl_0<>

Returns the minimum element in a sequence. If the sequence does not have elements, coveo::linq::empty_sequence is thrown.

Use like this:

const std::vector<int> YES = { 42, 23, 66, 11, 7 };
const std::vector<int> NAY;

using namespace coveo::linq;
auto min1 = from(YES)
          | min();
// min1 == 7
// This throws an exception:
// auto min2 = from(NAY)
//           | min();

Returns

(Once applied) Minimum element in sequence.

Exceptions

coveo::linq::empty_sequence

The sequence does not have elements.

min() [2/2]

template<typename Selector >

auto coveo::linq::min

(

const Selector &

sel

)

-> detail::min_impl_1<Selector>

Returns the minimum value in a sequence by projecting each element to a different value using the provided selector. If the sequence does not have elements, coveo::linq::empty_sequence is thrown.

Use like this:

const std::vector<int> YES = { 42, 23, 66, 11, 7 };
const std::vector<int> NAY;

using namespace coveo::linq;
auto min1 = from(YES)
          | min([](int i) { return -i; });
// min1 == -66
// This throws an exception:
// auto min2 = from(NAY)
//           | min([](int i) { return -i; });

Parameters

sel	Selector called to project each element into a different value.

Returns

(Once applied) Minimum projected value in sequence.

Exceptions

coveo::linq::empty_sequence

The sequence does not have elements.